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-4.9t^2+24.5t+8.9=t
We move all terms to the left:
-4.9t^2+24.5t+8.9-(t)=0
We add all the numbers together, and all the variables
-4.9t^2+23.5t+8.9=0
a = -4.9; b = 23.5; c = +8.9;
Δ = b2-4ac
Δ = 23.52-4·(-4.9)·8.9
Δ = 726.69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23.5)-\sqrt{726.69}}{2*-4.9}=\frac{-23.5-\sqrt{726.69}}{-9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23.5)+\sqrt{726.69}}{2*-4.9}=\frac{-23.5+\sqrt{726.69}}{-9.8} $
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